Answer:
A. 1.6 × 105 joules
Explanation:
As per the question, the data given in the question is as follows
Number of masses = 2
Each weightage = [tex]1.0 \times 2.3[/tex]
Speed = 12.5 meters/ second
Based on the above information, the approximate kinetic energy after the collision is
A perfectly elastic collision is described as one where the collision does not cause any loss of kinetic energy.
So we sum the kinetic energy of each kind of system which is given below:
Kinetic energy is
[tex]= 0.5(1.0 \times 10^3) (12.5)^2 + 0.5 (1.0 \times 10^3) (12.5 )^2[/tex]
= 156250 J
[tex]= 1.6 \times 10^5 J[/tex]
