Answer:
[tex]\mu = 101, \sigma =12[/tex]
And we want to find the percentage of no more than 125. We can use the z score formula given by:
[tex] z =\frac{X -\mu}{\sigma}[/tex]
And using the value given we got:
[tex] z=\frac{125-101}{12}=2[/tex]
From the empirical rule we know that within two deviations we have 95% of the values and in the tails 5%.
So we want the percentage below 2 deviations above the mean and the percentage would be (100- 2.5)=97.5%.
Step-by-step explanation:
We know the following parameters:
[tex]\mu = 101, \sigma =12[/tex]
And we want to find the percentage of no more than 125. We can use the z score formula given by:
[tex] z =\frac{X -\mu}{\sigma}[/tex]
And using the value given we got:
[tex] z=\frac{125-101}{12}=2[/tex]
From the empirical rule we know that within two deviations we have 95% of the values and in the tails 5%.
So we want the percentage below 2 deviations above the mean and the percentage would be (100- 2.5)=97.5%.
