Answer:
At least the 75% of the scores of driving exams are between 62 and 82 points.
Step-by-step explanation:
The chebyshev theorem said that the proportion of any distribution that is less than k deviations of the mean is at least [tex]1-\frac{1}{k^2}[/tex].
So, if we replace k by 2, we can calculated the limits as:
[tex]x+2s=72+2(5)=82\\x-2s=72-2(5)=62[/tex]
Where x is the mean and s is the standard deviation.
Then, [tex]1-\frac{1}{k^2}[/tex] is equal to:
[tex]1-\frac{1}{k^2}=1-\frac{1}{2^2}=0.75[/tex]
It means that at least the 75% of the scores of driving exams are between 62 and 82 points.
