Answer:
903 sq. cm.
Step-by-step explanation:
It is given that the length of two parallel sides of a trapezium are 91 cm and 51 cm and the length of two other side 37 CM and 13 cm respectively.
Now draw a dotted line as shown in the below figure. So, we have a triangle with sides 13 cm, 37 cm, 40cm and a parallelogram with sides 51 cm, 13 cm.
Area of parallelogram is
[tex]A_1=base\times height[/tex]
[tex]A_1=51\times 13[/tex]
[tex]A_1=663[/tex]
Using heron's formula, area of triangle is
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]
where, [tex]s=\dfrac{a+b+c}{2}[/tex].
The sides of triangle are 13cm, 37 cm, and 40 cm.
[tex]s=\dfrac{13+37+40}{2}=45[/tex]
Area of triangle is
[tex]A=\sqrt{45(45-13)(45-37)(45-40)}=240[/tex]
The area of trapezium is
[tex]A=A_1+A_2=663+240=903[/tex]
Therefore, the area of trapezium is 903 sq. cm.
