hanie17
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the coordinates of point G ar (4,-2) and the gradient of the straight line GH is -2.The coordinates of point H could be
A.(-1,6)
B.(-1,8)
C.(-1,10)
D.(-1,12)​

Respuesta :

CHERLYNnotCHERRY

Step-by-step explanation:

Given that the formula of gradient is :

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

So you have to try for every coordinates :

Option A,

[tex] \frac{6-(-2)}{-1-4} = - \frac{8}{5} (incorrect) [/tex]

Option B,

[tex] \frac{8-(-2)}{-1-4} = -2 (correct) [/tex]

Option C,

[tex] \frac{10-(-2)}{-1-4} = - \frac{12}{5} (incorrect) [/tex]

Option D,

[tex] \frac{12-(-2)}{-1-4} = - \frac{14}{5} (incorrect) [/tex]

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