Answer:
21+12i i hope this will help you
Step-by-step explanation:
(3-4i)(1+5i)-(2-i)
=[3(1+5i)-4i(1+5i)]-(2-i)
=[3+15i-4i-20i²]-(2-i)
=(3+11i-20i²)-(2-i)
opening brackeys
=3+11i-20i²-2+i
=3+11i+1i-20i²-2
as we know that i²=-1
=3-20(-1)-2+12i
=3+20-2+12i
=21+12i
