Answer:
The answer is C.
Step-by-step explanation:
You have to substitute the x-values into the equation to see whether it suits the y-value :
[tex]y = 2x[/tex]
[tex]let \: x = 0 \\ y = 2(0) \\ y = 0 \: (incorrect)[/tex]
[tex]let \: x = 2 \\ y = 2(2) \\ y = 4 \: (incorrect)[/tex]
[tex]let \: x = 1 \\ y = 2(1) \\ y = 2 \: (correct)[/tex]
[tex]let \: x = 2 \\ y = 2(2) \\ y = 4 \: (incorrect)[/tex]
