Answer:
Length of DE = 7.5 units
Length of DB = 9.2 units
Measure of ∠FED = 82°
Step-by-step explanation:
In ΔABC,
AD ≅ BD and CE ≅ BE [Given]
By the theorem of mid-segments,
DE = [tex]\frac{1}{2}(AC)[/tex]
= [tex]\frac{1}{2}(15)[/tex]
DE = 7.5 units
Since AD ≅ FE ≅ 9.2 [By midpoint theorem in ΔACB]
Therefore, length of DB = 9.2 units
[Although it's not given in the question, but we assume FE║AB]
Since FE║AB and DE is a transverse,
Therefore, m(∠FED) ≅ m(∠BDE) ≅ 82° [Interior alternate angles]
