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Ocean waves of wavelength 30m are moving directly toward a concrete barrier wall at 4.8m/s . The waves reflect from the wall, and the incoming and reflected waves overlap to make a lovely standing wave with an antinode at the wall. (Such waves are a common occurrence in certain places.) A kayaker is bobbing up and down with the water at the first antinode out from the wall.A) How far from the wall is she?B) What is the period of her up and down motion?

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Rau7star

Answer:

a)15m

b)6.25s

Explanation:

A) She is ½ a wavelength away, or

d = λ/2 = 30/2 = 15 m

B)Speed of the wave:

V=fλ = λ/T

so,

T=λ/V= 30/4.8

T=6.25s

a) The distance from the wall is 15m

b) The period of her up and down motion is 6.25s

Calculation of the distance and period is:

a.

Since Ocean waves of wavelength 30m are moving directly toward a concrete barrier wall at 4.8m/s .

Also,

She is ½ a wavelength away, or

d = λ/2

= 30/2

= 15 m

b)

Here the speed of wave should be used

T=λ/V

= 30/4.8

T=6.25s

Learn more about wavelength here: https://brainly.com/question/13524696

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