Answer:
EB = 6 units
Step-by-step explanation:
It is given that we have a circle and two cords AB and CD inside that circle.
AB and CD intersect each other at point E.
Also the values of AE, CE and ED are as follows:
AE = 2 units
CE = 4 units
ED = 3 units
To find: EB = ?
Please refer to the figure attached for a clear picture of the given dimensions.
The relation between intersecting cords is given as:
If the two cords are intersecting and they are divided in parts a, b and c,d
Then
a [tex]\times[/tex] b = c [tex]\times[/tex] d
Here,
a = AE = 2 units
c = CE = 4 units
d = ED = 3 units
b = EB = ?
Putting the values in formula:
2 [tex]\times[/tex] EB = 3 [tex]\times[/tex] 4
[tex]\Rightarrow EB = \dfrac{12}{2}\\\Rightarroe EB = 6\ units[/tex]
So, the answer is EB = 6 units
