Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of [tex]- 3\dfrac{1}{2}^0[/tex]
Step-by-step explanation:
A temperature falls from 0 to [tex]- 12\dfrac{1}{4}[/tex] in [tex]3\dfrac{1}{2} \ hours[/tex]
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is [tex]- 12\dfrac{1}{4}[/tex]
The change in temperature is [tex]\Delta T = T_2 - T_1[/tex]
[tex]\Delta T = -12\dfrac{1}{4} -0[/tex]
[tex]\Delta T = -12.25[/tex]
Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:
[tex]\dfrac{-12.25^0*1 }{3.5}=\dfrac{ x^0 *3.5}{3.5}[/tex]
x° = - 3.5
x° = [tex]- 3\dfrac{1}{2}[/tex]
Thus per hour; the temperature falls at the rate of [tex]- 3\dfrac{1}{2}^0[/tex]
Answer:
Negative StartFraction 7 over 2 EndFraction times StartFraction 49 over 4 EndFraction
Step-by-step explanation:
A
