Answer:
1.3g of Na
Explanation:
We'll begin by calculating the molar mass of sodium benzoate, NaC7H5O2. This is shown below:
Molar Mass of NaC7H5O2 = 23 + (12x7) + (5x1) + (17x2)
= 23 + 84 + 5 + 32
= 144g/mol
Now, we can obtain the mass of sodium, Na present in 8.4g of sodium benzoate, NaC7H5O2 as follow:
There are 23g of Na in 144g of NaC7H5O2.
Therefore, the mass of Na in 8.4g of NaC7H5O2 is given by:
23/144 x 8.4 = 1.3g.
Therefore, 1.3g of Na is present in 8.4g of sodium benzoate, NaC7H5O2.
