Answer:
The speed is [tex]v = 9.8 \ m/s[/tex]
Explanation:
From the question w are told that
The angle made is [tex]\theta = 30^o[/tex]
The distance above the surface of the water is [tex]h_{max} = 1.2 \ m[/tex]
The value of [tex]g = 10 \ m/s^2[/tex]
The maximum height attained by the fish is mathematically evaluate as
[tex]h_{max} = \frac{v^2 sin ^2 \theta }{2g }[/tex]
Making v which is the speed of the fish the subject of the formula
[tex]v = \sqrt{ \frac{2gh_{max}}{ sin^2 \theta } }[/tex]
substituting values
[tex]v = \sqrt{ \frac{2*10 *1.2 }{ [sin (30)]^2 } }[/tex]
[tex]v = 9.8 \ m/s[/tex]
