Answer:
The electric force is [tex]F = 11.9 *10^{-9} \ N[/tex]
Explanation:
From the question we are told that
The Bohr radius at ground state is [tex]a_o = 0.529 A = 0.529 ^10^{-10} \ m[/tex]
The values of the distance between the proton and an electron [tex]z = 2.63a_o[/tex]
The electric force is mathematically represented as
[tex]F = \frac{k * n * p }{r^2}[/tex]
Where n and p are charges on a single electron and on a single proton which is mathematically represented as
[tex]n = p = 1.60 * 10^{-19} \ C[/tex]
and k is the coulomb's constant with a value
[tex]k =9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.[/tex]
substituting values
[tex]F = \frac{9*10^{9} * [(1.60*10^{-19} ]^2)}{(2.63 * 0.529 * 10^{-10})^2}[/tex]
[tex]F = 11.9 *10^{-9} \ N[/tex]
