AOC is a straight line an dab the ratio of t he angles is: AOB: BOC: =4:11 what is the size of the angle AOB?

[tex]answer \\48 \\ solution \\ let \: the \: ratios \: of \: angles \: be \: 4x \: and \: 11x \\ 4x + 11x = 180(sum \: of \: angle \: in \: straight \: line) \\ or \: 15x = 180 \\ or \: x = \frac{180}{5} \\ x = 12 \\ again \\ < aob = 4x \\ \: \: \: \: \: = 4 \times 12 \\ \: \: \: \: \: \: \: \: \: \: = 48 \\ hope \: it \: helps[/tex]
Answer:
[tex]48 \: \: degrees[/tex]
Answer B is correct
Step-by-step explanation:
We know that,
Angels in a straight line = 180°
Let's get the ratio of angles as,
[tex] 4x: 11x[/tex]
Let's solve for x now.
[tex]4x + 11 = 180 \\ 15 = 180 \\ \frac{15x}{15} = \frac{180}{15} \\ x = 12 \\ [/tex]
Angle AOB = 4x
[tex]x = 12 \\ 4x = 12 \times 4 \\ = 48[/tex]
hope this helps you.
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