Respuesta :
Answer:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
Step-by-step explanation:
For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]
Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:
[tex] z_{\alpha/2}= \pm 1.62015[/tex]
And we can use the following excel code for example:
"=NORM.INV(0.0526,0,1)"
