Answer:
[tex]y - 5 = -4(x-5)[/tex]
Step-by-step explanation:
Given
Line coordinates: (5,5)
Perpendicular slope = [tex]\frac{1}{4}[/tex]
Required
Find the point slope form of the line
First, the slope of the line has t be calculated;
Given that two lines are perpendicular;
The relationship between there slopes is given as [tex]m_1.m_2 = -1[/tex]
Let m_2 represent the slope of the second line;
such that [tex]m_2 = \frac{1}{4}[/tex]
So;
[tex]m_1 * \frac{1}{4} = -1[/tex]
Multiply both sides by 4
[tex]m_1 * \frac{1}{4} * 4 = -1 * 4[/tex]
[tex]m_1 = -1 * 4[/tex]
[tex]m_1 = -4[/tex]
Now, the equation of the line can be calculated using slope formula;
[tex]m = \frac{y - y_1}{x- x_1}[/tex]
Where
[tex](x_1,y_1) = (5,5)\\m_1 =m = -4[/tex]
So; [tex]m = \frac{y - y_1}{x- x_1}[/tex] becomes
[tex]-4 = \frac{y - 5}{x- 5}[/tex]
Multiply both sides by x - 5
[tex]-4(x-5) = \frac{y - 5}{x- 5} * (x-5)[/tex]
[tex]-4(x-5) = y - 5[/tex]
Reorder
[tex]y - 5 = -4(x-5)[/tex]
Hence, the line in point-slope form is [tex]y - 5 = -4(x-5)[/tex]
