Answer:
[tex]T_{m }[/tex] = 4.86 s
[tex]T_{e}[/tex] = 1.98 s
Explanation:
Given:
Length = l = 1 m
Acceleration due to gravity of moon = [tex]g_{m}[/tex] = 1.67 m/s²
Acceleration due to gravity of Earth = [tex]g_{e}[/tex] = 10 m/s²
Required:
Time period = T = ?
Formula:
T = 2π [tex]\sqrt{\frac{l}{g} }[/tex]
Solution:
For moon
Putting the givens,
T = 2(3.14) [tex]\sqrt{\frac{1}{1.67} }[/tex]
T = 6.3 [tex]\sqrt{0.6}[/tex]
T = 6.3 × 0.77
T = 4.86 sec
For Earth,
Putting the givens
T = 2π [tex]\sqrt{\frac{1}{10} }[/tex]
T = 2(3.14) [tex]\sqrt{0.1}[/tex]
T = 6.3 × 0.32
T = 1.98 sec
