Respuesta :
Answer:
0.521 moles still present in the container.
Explanation:
It is possible to answer this question by using the general gas law, that is:
PV = nRT
Where P represents pressure of the gas, v its volume, n moles, R gas constant law and T absolute temperature (21.7°C + 273.15 = 294.85K)
Replacing with values of the initial conditions of the container, its volume is:
V = nRT / P
V = 2.00mol*0.082atmL/molK*294.85K / 3.75atm
V = 12.9L
When some gas is released, absolute temperature is 28.1°C + 273.15 = 301.25K, the pressure is 0.998atm and the volume of the container still constant. Again, using general gas law:
PV / RT = n
0.998atm*12.9L / 0.082atmL/molK*301.25K = n
0.521 moles = n
0.521 moles still present in the container.
Ideal gas law is the hypothetical equation in which the pressure, volume, and temperature of the gas are directly related. It can be denoted as:
PV = nRT
The number of moles still present in the container is 0.521.
The ideal gas law is:
PV = nRT
where,
P = Pressure
V = Volume
R = Gas constant
T =Temperature
n = moles
Given:
Moles in container = 2.00
Temperture = 294.85 K
Pressure = 3.75 atm
Volume =?
Substituting the values:
V = nRT/P
[tex]\text V&=\dfrac{2\times0.082 \times294}{3.75}[/tex]
Volume = 12.9 L
Now, the condition when changed, such that temperature is 301.25 K, pressure is 0.998 atm, and Volume is 12.9 L, then moles will be equal to:
[tex]\begin{aligned}\dfrac{\text{PV}}{\text{RT}}&=\text n\\\\\dfrac{0.998 \times 12.9} {0.082 \times 301.25}&=\text n\end[/tex]
n = 0.521 moles
Therefore, 0.521 moles is still present in the container.
To know more about ideal gas law, refer to the following link:
https://brainly.com/question/12124605
