Answer:
388.97 nm
Explanation:
The computation of the wavelength of this light in benzene is shown below:
As we know that
n (water) = 1.333
n (benzene) = 1.501
[tex]\lambda (water) \times n(water) = \lambda (benzene) \times n(benzene)[/tex]
And, the wavelength of water is 438 nm
[tex]\lambda (benzene) = \lambda (water) [\frac{n(water)}{n(benzene}][/tex]
Now placing these values to the above formula
So,
[tex]= 438 \times \frac{1.333}{1.501}[/tex]
= 388.97 nm
We simply applied the above formula so that we can easily determine the wavelength of this light in benzene could come
