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Triangle A B C. Angle C is 90 degrees. Hypotenuse A B is 26, adjacent side A C is 24, opposite C B is 10. For the triangle above, find sin A. a. 36° c. 0.9323 b. 50° d. 0.385

Triangle A B C Angle C is 90 degrees Hypotenuse A B is 26 adjacent side A C is 24 opposite C B is 10 For the triangle above find sin A a 36 c 09323 b 50 d 0385 class=

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Answer:

Option (D).

Step-by-step explanation:

In the figure attached,

ΔACB is a right triangle with AC = 24 units, BC = 10 units and AB = 26 units

For angle A,

Adjacent side = AC

Opposite side = BC

Hypotenuse = AB

SinA = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

        = [tex]\frac{BC}{AB}[/tex]

        = [tex]\frac{10}{26}[/tex]

SinA = 0.3846

        ≈ 0.385

Therefore, Option (D) will be the answer.

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