Answer:
[tex] AC = \sqrt(26) \approx 5.1 [/tex]
Step-by-step explanation:
The diagonals are AC and BD.
Now we find the lengths of the diagonals using the distance formula.
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
AC:
[tex] AC = \sqrt{(6 - 5)^2 + (7 - 2)^2} [/tex]
[tex] AC = \sqrt{(1)^2 + (5)^2} [/tex]
[tex] AC = \sqrt{1 + 25} [/tex]
[tex] AC = \sqrt{26} [/tex]
BD:
[tex] BD = \sqrt{(9 - 2)^2 + (5 - 4)^2} [/tex]
[tex] BD = \sqrt{(7)^2 + (1)^2} [/tex]
[tex] BD = \sqrt{49 + 1} [/tex]
[tex] BD = \sqrt{50} [/tex]
Since sqrt(26) < sqrt(50), then the shorter diagonal is AC.
Answer: AC = sqrt(26) or approximately 5.1
Answer:
A = (5.2)
Step-by-step explanation:
c2= (6-5)^2 + (7-2)^2
To find AC we calculate within parenthesis (6-5) : 1
c2= 1 + (7-2)^2
calculate within parenthesis (7-2) : 5
c2 = 1^2 + 5^2
then calculate exponents 1^2:1
c^2 = 1+5^2
add and subtract left to right
c^2 = 1+25
c^2 =26
Sr of 26 = 5.09901951359
Which means the closest answer is A = 5.2
To find BD we calculate within parenthesis (9-2):7
c2= (9-2)^2 + (5 - 4)^2
calculate within parenthesis (5-4) : 1
c2 = (7)^2 + (1)^2
calculate exponents 1 ^2 : 1
c2 = 49 +1
add and subtract left to right
c2 = 50
Sr of 50 = 7.07106781187
