Andy, 52, was very surprised when his doctor told him that his blood levels of vitamin D were below normal. After all, he plays tennis or rides a bike on most days. However, he forgot that the time for vitamin D synthesis from sun exposure is only from 10:00 AM to 1:00 PM for most locations in the United States, and he does most of his activities after work. Because his sun exposure is not adequate, he has to rely more on diet and supplements for his vitamin D needs. Andy's doctor asked him to consume 600 IU of vitamin D daily, He is supposed to track his vitamin D intake from foods and take a supplement if he does not meet his daily goal. It sounded easy, but he was up for a surprise. Some foods had the amounts of vitamin D listed in micrograms, others in IU. Most supplements have the amounts of vitamin.Below is Andy's vitamin D intake from the food he consumed yesterday Low-fat Yoplait yogurt-2 μg Cheerios cereal-1 μg Coffee with milk-07μg Turkey sandwich on whole-wheat bread with large garden salad-0.4 g Grilled pork chop. 8 oz. with mashed potato and a side of gnled mixed vegetables-1.6 μgA. How many IU of vitamin D did Andy consume yesterday? B. Has Andy met his vitamin D RDA? Does he need a supplement? 1. Yes, he met his RDA and does not need a supplement.2. No, his vitamin D intake was below RDA, and he needs a supplement.C. What percentage of the vitamin D RDA did Andy eat from food?

Respuesta :

Answer:

A. Total Vit D intake = 1150000212 IU

B. Yes he met his RDA and does not need any supplements

C. 191666702%

Explanation:

I μg = 40 IU

1 oz = 28.35 g

I g = 1000000 μg

A. Low-fat Yoplait yogurt-2 μg = 2 * 40 IU = 80 IU

Cheerios cereal-1 μg = 40 1U

Coffee with milk-07μg = 0.7 * 40 = 28 IU

Turkey sandwich on whole-wheat bread with large garden salad-0.4 g = 0.4 * 1000000 * 40 IU = 16000000 IU Grilledd pork chop. 8 oz = 28.35 * 1000000 * 40 = 1134000000 IU

mashed potato and a side of gnled mixed vegetables-1.6 μg = 1.6 * 40 = 64 IU

Total vitamin D intake = 1150000212 IU of Vit D.

B. Since his RDA is 600 IU, he met his RDA and does not need any supplements of Vit D.

C. Percentage of his RDA Vit D intake = (1150000212/600) * 100% = 191666702 %