Answer:
The answer is "70°"
Step-by-step explanation:
In the given question an attachment file is missing. so, the attachment file and its solution can be defined as follows:
Given:
ABC is the right triangle.
Find B=?
Solution:
[tex]\Rightarrow \sin \theta= \frac{p}{h}\\\\[/tex]
[tex]\Rightarrow \sin B^{\circ}=\frac{AB}{AC}= \frac{4.8}{5.1}\\\\[/tex]
[tex]\Rightarrow \sin B^{\circ}= .941[/tex]
[tex]\Rightarrow B^{\circ}= \sin^{-1} (0.941)\\\\\bold{\sin^{-1} (0.941) = 70.2^{\circ}}\\\\\therefore \ \ \ \ \bold{B^{\circ} = 70^{\circ}}[/tex]
