We have that the trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows
From the question we have that
Distance [tex]d=1.00cm=0.01m[/tex]
Magnitude [tex]M=1,920 N/C[/tex]
Mass [tex]m=2.00x10^{-16} kg[/tex]
Charge [tex]q=1.02x10^{-6} C[/tex]
initial speed [tex]V_0= 1.07x10^5 m/s[/tex]
Angle [tex]\theta= 37[/tex]
Length [tex]l= 20.0 cm.[/tex]
a)
The Particle follow a Parabola trajectory through its travel as a Parabola Creates a Curved Plane and has its initial half side same as the final side.with the particle is a [tex]\theta= 37[/tex] angle create on its elevation and depression
Parabola
b)
It strikes the Negative plate at a specific distance to be discovered in the C part of the Question
c)
We are tasked to determine where the particle strikes the plate.
Generally the equation for strike distance S is mathematically given as
[tex]s=\frac{v_0^2 sin(2\theta)}{a}[/tex]
Where
[tex]a=\frac{qM}{m}[/tex]
[tex]a=\frac{1.02x10^{-6}x1920}{2.00x10^{-16} }[/tex]
[tex]a=9.792x10^{12}m/s^2[/tex]
Therefore
[tex]s=\frac{v_0^2 sin(2\theta)}{a}[/tex]
[tex]\frac{(1.07x10^5)^2 xsin(2*37)}{9.792x10^{12}}[/tex]
[tex]s=0.0011239m[/tex]
d)
Generally the equation for the minimum Velocity is mathematically given as
[tex]V_m=\sqrt{\frac{2ah}{sin(\theta)}}[/tex]
[tex]V_m=\sqrt{\frac{2x9.792*10^{12}*0.01}{sin(37)}}[/tex]
[tex]V_m=570452.106m/s[/tex]
In conclusion
The trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows
For more information on this visit
https://brainly.com/question/1470439
