A force of 2500 N is exerted on a piston that has an area of 0.060 m2. What
force is exerted on a second piston that has an area of 0.18 m?

F F2
Α1, Α2,

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Respuesta :

ABDERRAMAN ABDERRAMAN · Answer 1 · 2020-06-24T00:58:20+02:00

Explanation:

SI LA PRESIÓN ES LA MISMA ENTONCES:

P = 2500 N/[tex]0.060 m^{2}[/tex] = 41667 Pa

F2 = 41667 Pa([tex]0.18 m^{2}[/tex]) = 7500 N

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sp10925 sp10925 · Answer 2 · 2022-07-20T06:59:44+02:00

The force is exerted on a second piston will be 7500N.

The pressure is the amount of force applied per unit area.

Pressure p = Force/Area

Given is a force of 2500 N is exerted on a piston that has an area of 0.060 m². Area of the second piston is 0.18m².

The pressure will be same for both the piston

P1 =P2

F1/A1 = F2/A2

Put the values, we get

2500 /0.060 = F2/0.18

F2 = 7500 N

Hence, force exerted on the second piston is 7500 N.

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