hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 EndLayout? StartLayout Enlarged left-brace 1st row y = negative 2 y squared minus 2 2nd row x = y minus 2 EndLayout StartLayout Enlarged left-brace 1st row y = negative 2 y squared + 2 2nd row x = y + 2 EndLayout StartLayout Enlarged left-brace 1st row y = negative 2 y squared minus 8 y minus 8 2nd row x = y + 2 EndLayout StartLayout Enlarged left-brace 1st row y = negative 2 y squared + 8 y minus 8 2nd row x = y minus 2 EndLayout

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austinomg123 austinomg123 · Answer 1 · 2020-06-26T02:36:27+02:00

Answer:

3rd Option

Step-by-step explanation:

Which equation is the inverse of y = 7x2 – 10?

y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction

y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot

x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot

y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction

abidemiokin abidemiokin · Answer 2 · 2021-10-11T11:57:35+02:00

A clearer question:

Which equation is the inverse of y = 7x² – 10

The required inverse of the given function is expressed as [tex]y=\sqrt{\frac{x+10}{7}}[/tex]

Step 1: Replace y with x

x = 7y² – 10

Step 2: Make y the subject of the formula:

7y² = x+ 10

Step 3: Divide both sides by 7

7y²/7 = (x+10)/ 7

y² = (x+10)/ 7

Step 4; Take the square root of both sides

[tex]\sqrt{y^2} =\sqrt{\frac{x+10}{7} } \\y = \sqrt{\frac{x+10}{7} } \\[/tex]

Hence the required inverse of the given function is expressed as [tex]y=\sqrt{\frac{x+10}{7}}[/tex]

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