Answer:
The probability that people have diastolic blood pressure less than 90
P( X< 90) = 0.6628
Step-by-step explanation:
Explanation:-
Given mean of the Population 'μ'= 85
Given standard deviation of the Population 'σ'= 12
Let 'X' be the Normal distribution
let X = 90
[tex]Z = \frac{x-mean}{S.D}[/tex]
[tex]Z = \frac{90-85}{12} = 0.4166 > 0[/tex]
The probability that people have diastolic blood pressure less than 90
P( x < 90) = P( Z < 0.4166)
= 1 - P( Z> 0.4166)
= 1 - (0.5 - A( 0.4166)
= 0.5 + 0.1628
= 0.6628
Conclusion:-
The probability that people have diastolic blood pressure less than 90
P( X< 90) = 0.6628
