Answer:
The given pedigree analysis shows sex-linked trait where the female work as a carrier and have X linked recessive gene that is [tex]X^{h}[/tex] and the male is normal.
So, Fred will be a male with [tex]X^{h}[/tex][tex]Y[/tex] gene and Fred will be affected with X linked disease which is carried by female.
If, [tex]X^{h}[/tex] gene in the female (Ann) act as a carrier of hemophilia and the male (John) is normal, then Fred will be a male affected with hemophilia (sex linked disease).
Hence, Fred will be affected male with [tex]X^{h}[/tex][tex]Y[/tex] genotype.
