Answer:
Hypotenuse = 13.798 cm, Angle1 = 27.4° and Angle2 = 62.59°
Step-by-step explanation:
The first step to help us understand the question would be to draw it out.
A right angled triangle, with the two sides that make the right angle being x and y (it does not matter which way you put x and y).
I have attached the quick sketch I will refer to.
To find the length of the hypotenuse (lets call it H) we can use Pythagoras theorem as shown below
[tex]{x^{2}+y^{2}} = H^{2}[/tex]
Substitute in our values for x and y, and solve for H
[tex]{6.35^{2}+12.25^{2}} = H^{2}[/tex]
[tex]190.385 = H^{2}[/tex]
[tex]\sqrt{190.385} = H[/tex]
H = 13.79 cm
To find the other two angles of the triangle we will use trigonometry
I will first look for angle ∅. Since we have all three sides of the triangle we can use any of the three trig functions, I chose to use Tan
Tan ∅ [tex]= \frac{opposite}{adjacent}[/tex]
Substitute in our values for x and y, and solve for ∅
Tan ∅ = [tex]\frac{6.35}{12.25}[/tex]
∅ = [tex]tan^{-1} \frac{6.35}{12.25}[/tex]
∅ = 27.4°
Now do the same for angle β. I chose to use Tan again
Tan β [tex]= \frac{opposite}{adjacent}[/tex]
Substitute in our values for x and y, and solve for β
Tan β = [tex]\frac{12.25}{6.35}[/tex]
β = [tex]tan^{-1} \frac{12.25}{6.35}[/tex]
β = 62.59°
