Answer: h = -(16t + 3)(t - 2)
h(0) = 6
h(1) = 19
h(2) = 0
Step-by-step explanation:
Factor the equation by finding two numbers whose
product = a×c and sum = b, then replace the b value with those two numbers and factor the equation.
h = -16t² + 29t + 6
a=-16 b=29 c=6 a×c = -96 b = 29
32 × -3 = 96 32 + (-3) = 29
h = -16t² + 32t -3t + 6
h = -16t(t - 2) -3(t - 2)
h = (-16t - 3) (t - 2)
h = -(16t + 3)(t - 2)
h(0) = -[16(0) + 3] [0 - 2]
= -(3)(-2)
= 6
h(1) = -[16(1) + 3] [1 - 2]
= -(19)(-1)
= 19
h(2) = -[16(2) + 3] [2 - 2]
= -(35)(0)
= 0
