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We know that if the probability of an event happening is 100%, then the event is a certainty. Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person, there would be a 100% chance of contracting the disease if 2 contacts were made with the infected person

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Answer:

The correct answer to the following question will be "No". The further explanation is given below.

Step-by-step explanation:

Probability (Keeping the disease out of 1 contact)

= [tex]0.5[/tex]

Probability (not keeping the disease out of 1 contact)

= [tex]1-0.5[/tex]

= [tex]0.5[/tex]

Now,

Probability (not keeping the disease out of 2 contact)

= Keeping the disease out of 1 contact × not keeping the disease out of 1 contact

On putting the estimated values, we get

= [tex]0.5\times 0.5[/tex]

= [tex]0.25[/tex]

So that,

Probability (Keeping the disease out of 2 contact)

= [tex]1-0.25[/tex]

= [tex]0.75 \ i.e., 75 \ percent[/tex]

∴  Not 100%