Answer:
[tex] P =\frac{F}{A}[/tex]
And solving for F we got:
[tex] F = PA[/tex]
And replacing we got:
[tex] F = 2.2x10^5 Pa * 0.088 m^2 =19360 N[/tex]
And if we want the mass we can solve from this formula:
[tex] F =mg[/tex]
With g=9.8 m/s^2 the gravity
Explanation:
For this case we can find the total area of the 4 tires and we got:
[tex] A = 4*0.022 m^2 = 0.088m^2[/tex]
Now we know that the total pressure is:
[tex] P=2.2 x10^5 Pa[/tex]
And then we can find the weight with from this formula:
[tex] P =\frac{F}{A}[/tex]
And solving for F we got:
[tex] F = PA[/tex]
And replacing we got:
[tex] F = 2.2x10^5 Pa * 0.088 m^2 =19360 N[/tex]
And if we want the mass we can solve from this formula:
[tex] F =mg[/tex]
With g=9.8 m/s^2 the gravity