Answer:
4.197 N
Explanation:
current through the wires I = 700 A
distance between wires r = 70 cm = 0.7 m
length of each wire L = 30 m
force per unit length on the wires is given as
[tex]\frac{F}{L}[/tex] = [tex]\frac{u*I^{2} }{2\pi r }[/tex]
where u = permeability of vacuum = 1.256 [tex]10^{-6}[/tex] m-kg-[tex]s^{-2}[/tex][tex]A^{-2}[/tex]
F = [tex]\frac{u*I^{2}L }{2\pi r }[/tex]
F = [tex]\frac{1.256*10^{-6} *700^{2}*30 }{2*3.142*0.7 }[/tex] = 4.197 N
