Respuesta :
Answer:
average angular speed = 196.92 rad/s
Explanation:
Given data
accelerates down = 0.40 m/s²
down hill travel = 85-m
travels top of hill = 1.8 m/s
radius wheels = 2.6 cm
Solution
We will apply here equation of motion that is express as
[tex]v^{2}-u^{2}[/tex] = 2as ...............1
here v is final velocity and u is final velocity and s is dispalement
so put here value we get first final velocity
[tex]v^{2} = 1.8^{2}[/tex] + 2 × 0.40 × 85
solve it we get
[tex]v^{2}[/tex] = 71.24
v = 8.44 m/s
and
initial angular speed is express as
initial angular speed ω = [tex]\frac{u}{r}[/tex] ............2
put here value
initial angular speed ω = [tex]\frac{1.8}{2.6 \times 10^{-2}}[/tex]
initial angular speed ω = 69.23 rad/s
and
final angular speed ω = [tex]\frac{v}{r}[/tex] ..............3
put here value
final angular speed ω = [tex]\frac{8.44}{2.6 \times 10^{-2}}[/tex]
final angular speed ω = 324.61 rad/s
so now we get average of angular speed that is
average angular speed = ( 69.23 + 324.61 ) ÷ 2
average angular speed = 196.92 rad/s
