Please answer this ASAP!!

Answer: The cost to buy all the paint he needs = [tex]\pounds \ 176.70\ .[/tex]
Step-by-step explanation:
Formula: Area of trapezium = [tex]\dfrac{1}{2}(a+b)h[/tex], where a and b are the parallel sides and h is the height.
From the given figure of trapezium, we have
a = 10 m
b = 16 m
h = 7.6 m
Then, area of trapezium floor = [tex]\dfrac{1}{2}(10+16)(7.6)=\dfrac{1}{2}(26)(7.6)=98.8\ m^2[/tex]
Also, 1 litre paint is required to paint and area of [tex]1.9\ m^2[/tex].
Then, the amount of paint required to paint [tex]98.8\ m^2[/tex] area = [tex](98.8\ m^2)\div(1.9\ m^2)[/tex]
[tex]= 52[/tex] litres
Since cost if 5 litres of paint = [tex]\pounds\ 16.99[/tex]
then cost of 1 liter paint = [tex]\pounds \dfrac{16.99}{ 5}=\pounds 3.398[/tex]
Then, cost of 52 litres of paint = [tex]52\times3.398=\pounds \ 176.696\approx\pounds\ 176.70[/tex]
Hence, the cost to buy all the paint he needs = [tex]\pounds \ 176.70\ .[/tex]