Answer:
the speed of the fluid in the wider section of the pipe is 1m/s.
Explanation:
By equation of continuity we can write (for ideal (non-viscous, in-compressible).
[tex]A_1v_1 =A_2v_2[/tex]
A_1,A_2 are areas of the pipe at inlet and outlet of the pipe.
[tex]\Rightarrow \pi d_1^2v_1=\pi d_2^2v_2[/tex]_1
Here, d_1 , d_2 are diameters of inlet and outlet, also v_1, v_2 are velocities at inlet and outlet.
putting values we get
[tex]\Rightarrow \p 0.7^2\times9=\pi 2.1^2\timesv_2[/tex]
solving we get
[tex]v_2= 1m/s[/tex]