A wire carries a current of 4 A travelling to the left (-x direction). It is placed in a constant magnetic field of magnitude 0.05 T, pointing upward ( z direction). a. If 25 cm of the wire is in the magnetic field, what is the force on the current

Respuesta :

Answer:

0.05 N

Explanation:

Data provided in the question

The Wire carries a current of 4A to the left direction

The constant magnetic field of magnitude = 0.05 T

Pointing upward i.e Z direction

The wire is in the magnetic field = 25 cm

Based on the above information, the force on the current is

[tex]= Current \times constant\ magnetic\ field\ of\ magnitude \times magnetic\ field[/tex]

[tex]= 4 \times 0.05 \times 0.25[/tex]

= 0.05 N

The direction will be the negative Y direction