Answer:
Step-by-step explanation:
We can write some equations to describe the given relationships:
A = B - 2 . . . . . A is 2 kg lighter than B
A = C/5 . . . . . . A is 1/5 the weight of C
A+C = 3B . . . . together, A and C are 3 times the weight of B
__
Let's solve for A.
B = A+2 . . . from the first equation
C = 5A . . . . from the second equation
A +5A = 3(A+2) . . . . substituting for B and C in the third equation
6A = 3A +6
3A = 6
A = 2
__
B = A+2 = 4
C = 5A = 10
Watermelon A weighs 2 kg; B weighs 4 kg; and C weighs 10 kg.
