Answer:
(7, 13/3)
Step-by-step explanation:
[tex]y=\frac{1}{3} x+2\\[/tex] Line up the equations on top of each other
[tex]y=\frac{4}{3} x-5[/tex]
[tex]-4*[y=\frac{1}{3} x+2][/tex] Multiply the top equation by [tex]-4[/tex] in order to cancel out the [tex]x[/tex] variable
[tex]-4y=-\frac{4}{3} x-8[/tex] Switch out the first equation for this one
[tex]-4y=-\frac{4}{3} x-8[/tex] Line up the equations
[tex]y=\frac{4}{3} x-5[/tex]
[tex]-3y=-13[/tex] Add the two equations top to bottom, left to right
[tex]y=\frac{13}{3}[/tex]
Now that you've found [tex]y[/tex], you need to find [tex]x[/tex]. Just plug in the y-value to either of the equations in Step 1:
The first equation has smaller numbers, so let's use that one.
[tex]\frac{13}{3} =\frac{1}{3} x+2[/tex]
To make it easier you can multiply all the terms in the equation by 3:
[tex]13=x+6[/tex]
[tex]7=x[/tex]
The [tex]x[/tex]- and [tex]y[/tex]- values together give a solution of ( [tex]7[/tex], [tex]\frac{13}{3}[/tex] )
