Answer:
The frequency shift detected is [tex]\Delta f =1010.3 Hz[/tex]
Explanation:
From the question we are told that
The normal frequency of the state highway patrol radar guns [tex]f = 8.66 GHz = 8.66 *10^{9} \ Hz[/tex]
The speed of approach is [tex]v = 35 .0 \ m/s[/tex]
Now the frequency measure by the the state highway patrol radar guns as your car approaches is mathematically represented as
[tex]f_n = f (1 + \frac{v}{c} )[/tex]
Where c is the speed of light which a has constant value of
[tex]c = 3.0 *10^{8 } \ m/s[/tex]
Now
[tex]f_n - f = \frac{fv}{c} )[/tex]
=> [tex]\Delta f = \frac{fv}{c}[/tex]
substituting values
[tex]\Delta f = \frac{ 8.66 *10^{9} * 35}{3.0 *10^8 }[/tex]
[tex]\Delta f =1010.3 Hz[/tex]
