What is the y-intercept of the line perpendicular to the line y = four thirdsx + 1 that includes the point (4, 1)?



2


negative thirteen thirds


4


negative nineteen thirds

Respuesta :

Answer:

(C)4

Step-by-step explanation:

Given the line: [tex]y=\dfrac43 x+1[/tex]

The gradient of the line, [tex]m=\dfrac43[/tex]

A line perpendicular to the given line will have a gradient, [tex]m=-\dfrac34[/tex] (by definition of perpendicularity).

Therefore, a perpendicular line that passes through the point (4,1) is:

[tex]y-y_1=m(x-x_1)\\y-1=-\dfrac34(x-4)\\y-1=-\dfrac34x+3\\y=-\dfrac34x+3+1\\y=-\dfrac34x+4[/tex]

Comparing with the slope-intercept form y=mx+x, the slope of the perpendicular line, b=4.

Answer:

it is c

Step-by-step explanation: