Find the equations for a conical helix that has a radius of 8, a height of 12 and does exactly two complete revolutions (starting at the xy-plane). Include a plot of your conical helix.

Respuesta :

Answer:

The equation are

    [tex]x =\frac{ 12-z }{h} 8 cos (2 z)[/tex]

    [tex]y = \frac{12-z }{12} 8sin (2z)[/tex]

    z = z

Step-by-step explanation:

From the question we are told that

   The radius of the conical helix is  [tex]r= 8[/tex]

    The height of the conical helix is  [tex]h = 12[/tex]

    The angular frequency  is  [tex]w = 2[/tex]

The plot of the conical helix is  shown on the first uploaded image

 Generally  the parametric equation of a conical helix is mathematically represented as

for x -axis

     [tex]x =\frac{ h-z }{h} r cos (wz)[/tex]

substituting values

      [tex]x =\frac{ 12-z }{h} 8 cos (2 z)[/tex]

for  y-axis

     [tex]y = \frac{h-z }{h} rsin (wz)[/tex]

substituting values

      [tex]y = \frac{12-z }{12} 8sin (2z)[/tex]

for  z-axis

   z = z

Ver imagen okpalawalter8