Answer:
The induced voltage in the coil is 0.25 V.
Explanation:
It is given that,
Area of a square coil is 2 cm or 0.02 m
Number of turns in the wire is 2500
A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.
We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V[/tex]
So, the induced voltage in the coil is 0.25 V.
