Answer:
[tex]rate=-1.75x10^{-5}\frac{M}{s}[/tex]
Explanation:
Hello,
In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:
[tex]rate=\frac{1}{2}*\frac{C_f-C_0}{t_f-t_0}[/tex]
Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript f is referred to the final condition and the subscript 0 to the initial condition, thus, we obtain:
[tex]rate=\frac{1}{2}*\frac{0.00650M-0.0100M}{100s-0s}\\\\rate=-1.75x10^{-5}\frac{M}{s}[/tex]
Clearly, it turns out negative since the concentration is diminishing due to its consumption.
Regards.
