Respuesta :

ronhagrid310

Answer:

The sum = 4092

Step-by-step explanation:

The sum is equal to A, in which:

A = 4 x (2^0 + 2^1 + 2^2 + ... + 2^9)

   = 4 x [(1 + 2^1 + 2^2 + ... + 2^9)(2 - 1)/(2 - 1)]

   = 4 x (2^10 - 1)(2 - 1)

   = 4 x (2^10 - 1)

  = 4 x  1023

  = 4092

Hope this helps!

Answer:

4092

Step-by-step explanation:

The n th term of a geometric sequence is

[tex]a_{n}[/tex] = a[tex]r^{n-1}[/tex]

where a is the first term and r the common ratio

4[tex](2)^{n-1}[/tex] ← is the n th term of a geometric sequence

with a = 4 and r = 2

The sum to n terms of a geometric sequence is

[tex]S_{n}[/tex] = [tex]\frac{a(r^{n}-1) }{r-1}[/tex] , thus

[tex]S_{10}[/tex] = [tex]\frac{4(2^{10}-1) }{2-1}[/tex] = 4(1024 - 1) = 4 × 1023 = 4092

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