If a transformer doubles its input voltage, what is the current in the secondary coil if the primary coil is 10 A.

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abidemiokin abidemiokin · Answer 1 · 2020-07-03T02:59:57+02:00

Answer:

20Amp

Explanation:

Using the transformer formula

Vs/Vp = Ns/Np = Ip/Is

Vs/Vp = Ip/Is

Vp is the primary voltage = input voltage

Vs is the secondary voltage = output voltage

Ip is the current in the primary coil

Is is the amount of current in the secondary coil.

If the transformer doubles its input voltage Vp, its output voltage Vs will be

decreased by 2 but the output current will be doubled

Given the input current Ip = 10A, the current in the secondary coil (output current) will be doubled i.e Is = 2(10) = 20A

Cricetus Cricetus · Answer 2 · 2022-04-03T12:57:45+02:00

The current in the secondary coil be "50 A". To understand the calculation, check below.

According to the question,

Current in primary coil, [tex]I_{in}[/tex] = 10 A

We know the relation,

Power = [tex]V_{in} I_{in}[/tex] = [tex]V_{out} I_{out}[/tex]

then,

→ [tex]V_{in} I_{in}[/tex] = [tex]V_{out} I_{out}[/tex]

By substituting the values,

[tex]V_{in}[/tex] × 10 = 2 [tex]V_{in} I_{out}[/tex]

By applying cross-multiplication,

10 = 2 [tex]I_{out}[/tex]

[tex]I_{out}[/tex] = [tex]\frac{10}{2}[/tex]

= 5 A

Thus the response above is correct.

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