PLZ HELP
What is the surface area of this rectangular pyramid?

Answer: ≈318.54
Area
Step-by-step explanation:
A=lw+l[tex]\sqrt{(w/2)^2+h^2+w}[/tex][tex]\sqrt{(l/2)^2+h^2}[/tex][tex]12*8+12*\sqrt{(8/2)^2+10^2+8} *\sqrt{(12/2)^2+10^2} =318.54[/tex]
Answer:
304 square meters
Step-by-step explanation:
here is why,
area of a triangle formula is:
A = bh/2, so
12 * 10/ 2 = 60
we multiply this by two (for each triangle face with these dimensions) to get 120. then we do the same for the other two trangular faces.
8 * 11/2 = 44
we multiply by two again to get 88.
finally, for the base
12 * 8 because area of a rectangle formula is:
A = L * W
12 * 8 = 96
we get our final answer by adding everything up to get 96 + 88 + 120 = 304