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Brass is made from a mixture of copper and other elements. A mixture that is 80% copper is combined with a mixture that is 60% copper, resulting in 100 pounds of brass that is 65% copper.

Which equation can be used to find x, the amount of 60% mixture used to create the 65% mixture?

0.8(100 – x) + 0.6x = 100(0.65)
0.6(100 – x) + 0.8x = 100(0.65)
0.8(100) + 0.6x = 0.65(100 - x)
0.6(x) + 0.8(100 + x) = 0.65

Respuesta :

Answer:

a.0.8(100 – x) + 0.6x = 100(0.65)

Step-by-step explanation:

The easiest way to find the answer is to derive the equation from the the data given.

The amount of 60% mixture is given as .

The amount of copper from 60% mixture =

The amount of copper from 80% mixture =

Therefore total amount of copper in 100 pound mixture is:

The amount of copper from 60% mixture + The amount of copper from 80% mixture

We can rearrange the equation as:

Percentage of copper in the final mixture can be derived by:

[Total pounds of copper/Total pounds of the mixture]×100

Percentage of copper in the final mixture is given as 65%

Therefore,

[Total pounds of copper/Total pounds of the mixture]×100=65%

This equation can be used to find the value of ..

Therefore the answer is a.0.8(100 – x) + 0.6x = 100(0.65)

The proportion of copper in each component of the resulting mixture is the

component that they contribute to the resulting mixture.

  • The equation that can be used to find x, the amount of 60% mixture used to create the 65% mixture is; [tex]\underline{0.8 \cdot (100 - x) + 0.6 \cdot x = 100 \cdot (0.65)}[/tex]

Reasons:

The given parameters are;

Percentage of copper in one of the mixture = 80%

Percentage of copper in one of the other mixture = 60%

Percentage of copper in the resulting 100 pounds = 65%

The amount of the 60% mixture used in the 65% mixture = x

Therefore;

The amount of the 80% mixture used in the 65% mixture = 100  - x

Mass of copper from 60% mixture in the resulting mixture = 0.6·x

Mass of copper from 80% mixture in the resulting mixture = 0.8·(100 - x)

Mass of copper in the resulting mixture = 100 × 0.65

Which gives;

[tex]\underline{0.8 \cdot (100 - x) + 0.6 \cdot x = 100 \cdot (0.65)}[/tex]

Learn more about the concentration of mixtures here:

https://brainly.com/question/25083728

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