Answer:
see below
Step-by-step explanation:
6 cot ^2 (y) ( sec^2 (y) -1) = 6
We know that ( sec^2 (y) -1) = tan ^2(y)
6 cot ^2 (y) tan ^2 (y) = 6
We know cot = cos/ sin and tan = sin / cos
6 cos/ sin ^2 (y) sin/cos ^2 (y) = 6
6 ( 1) = 6
6=6
See below
[tex]6\cot^2(\gamma)(\sec^2(\gamma)-1)=6\\\\\\\\cot^2(\gamma)(\sec^2(\gamma)-1)=1\\\\\\\dfrac{\cos^2(\gamma)}{\sin^2(\gamma)}\left(\dfrac{1}{\cos^2(\gamma)}-1\right)=1\\\\\\\dfrac{1}{\sin^2(\gamma)}-\dfrac{\cos^2(\gamma)}{\sin^2(\gamma)}=1 \\\\\\\csc (\gamma) - \cot (\gamma)=1 \\\\\\1=1 \\\\QED[/tex]
Hope this helps!
